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Home » 1.25^2 = 1.5625 - RedTag Digital

1.25^2 = 1.5625 - RedTag Digital

📅 May 17, 2026 👤 scraface

May 17, 2026

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L(m) = (m)^2 - 2m(m) + m^2 + 4 = m^2 - 2m^2 + m^2 + 4 = 0 + 4 = 4
But the problem states the minimum loss must be 1, yet we get 4. This...
L(m) = m^2 - 2m \cdot m + m^2 + 4 = 2m^2 - 2m^2 + 4 = 4
So the minimum value is always 4, independent of \( m \). But the prob...
Wait — re-examining: perhaps a typo in interpretation. Let’s suppose t...
Thus minimum value is \( 0 + 4 = 4 \), always. So minimum cannot be 1.
But the problem says "find \( m \) such that the minimum loss is exact...
Wait — perhaps the function is \( L(w) = w^2 - 2mw + m^2 + c \), and \...
Given \( L(w) = w^2 - 2mw + m^2 + 4 = (w - m)^2 + 4 \), minimum is alw...
But perhaps the problem meant: find \( m \) such that the **minimum va...

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